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For the ellipse (x^(2))/(a^(2))+(y^(2))/...

For the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2)) =1` and `(x^(2))/(b^(2))+(y^(2))/(a^(2)) =1`

A

(a) The foci of each ellipse always lie within the other ellipse

B

(b) Their auxiliary circles are the same

C

(c) Their director circles are the same

D

(d) The ellipses encloses the same area

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To solve the problem regarding the two ellipses given by the equations \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) and \(\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\), we will analyze each option provided in the question step by step. ### Step 1: Identify the Foci of Each Ellipse 1. **First Ellipse**: The foci of the ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) (where \(a > b\)) are given by the formula \((\pm ae, 0)\), where \(e = \sqrt{1 - \frac{b^2}{a^2}}\). 2. **Second Ellipse**: The foci of the ellipse \(\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\) (where \(a > b\)) are given by \((\pm be', 0)\), where \(e' = \sqrt{1 - \frac{a^2}{b^2}}\). **Conclusion**: The foci of the first ellipse are always on the x-axis, while the foci of the second ellipse can be either inside or outside depending on the values of \(a\) and \(b\). Therefore, the first option is **incorrect**. ### Step 2: Determine the Auxiliary Circles 1. **Auxiliary Circle of First Ellipse**: The auxiliary circle for the first ellipse is given by the equation \(x^2 + y^2 = a^2\). 2. **Auxiliary Circle of Second Ellipse**: The auxiliary circle for the second ellipse is also given by the equation \(x^2 + y^2 = a^2\). **Conclusion**: Since both ellipses have the same auxiliary circle, the second option is **correct**. ### Step 3: Find the Director Circles 1. **Director Circle of First Ellipse**: The equation of the director circle for the first ellipse is \(x^2 + y^2 = a^2 + b^2\). 2. **Director Circle of Second Ellipse**: The equation of the director circle for the second ellipse is also \(x^2 + y^2 = a^2 + b^2\). **Conclusion**: Both ellipses have the same director circle, so the third option is **correct**. ### Step 4: Calculate the Area of Each Ellipse 1. **Area of First Ellipse**: The area of the first ellipse is given by the formula \(A_1 = \pi ab\). 2. **Area of Second Ellipse**: The area of the second ellipse is also given by the formula \(A_2 = \pi ab\). **Conclusion**: Both ellipses enclose the same area, thus the fourth option is **correct**. ### Final Conclusion The correct options are: - Option B (Auxiliary circles are the same) - Option C (Director circles are the same) - Option D (Ellipses enclose the same area)

To solve the problem regarding the two ellipses given by the equations \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) and \(\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\), we will analyze each option provided in the question step by step. ### Step 1: Identify the Foci of Each Ellipse 1. **First Ellipse**: The foci of the ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) (where \(a > b\)) are given by the formula \((\pm ae, 0)\), where \(e = \sqrt{1 - \frac{b^2}{a^2}}\). 2. **Second Ellipse**: The foci of the ellipse \(\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\) (where \(a > b\)) are given by \((\pm be', 0)\), where \(e' = \sqrt{1 - \frac{a^2}{b^2}}\). **Conclusion**: The foci of the first ellipse are always on the x-axis, while the foci of the second ellipse can be either inside or outside depending on the values of \(a\) and \(b\). Therefore, the first option is **incorrect**. ...
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