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Find the equation of the circle which to...

Find the equation of the circle which touches the x-axis and whose center is (1, 2).

Text Solution

Verified by Experts

The correct Answer is:
`x^(2)+y^(2)-2x-4y+1=0`
The center is (1,2) and since since the circle touches the x-axis , the radius is equal to 2.
Hence, the equation is
`(x-1)^(2)+(y-2)^(2)=2^(2)`
or `x^(2)+y^(2)-2x-4y+1=0`
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Knowledge Check

  • The equation of the circle which touches x-axis and whose centre is (1,2) is

    A
    (a) `x^(2) + y^(2)- 2x - 4y + 4 = 0 `
    B
    (b) `x^(2) + y^(2) - 2x - 4y + 1= 0 `
    C
    (c) ` x^(2) + y^(2) + 2x + 4y - 1 = 0 `
    D
    (d) `x^(2) + y^(2) + 2x - 4y + 1 = 0 `

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