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If the y=mx+1, of the circle x^2+y^2=1 s...

If the `y=mx+1,` of the circle `x^2+y^2=1` subtends an angle of measure `45^@` of the major segment of the circle then value of `m` is -

A

2

B

`-2`

C

`-1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
3

The given circle is `x^(2)+y^(2)=1`. Center, `C-=(0,0)` radius `=1`, and chord is `y=mx+1`.
`cos 45^(@)=(CP)/(CR)`

Perpendicular distance from `(0,0)` to the chord `y=mx+1`
`CP=(1)/(sqrt(m^(2)+1))`
or `cos 45^(@)=(1//sqrt(m^(2)+1))/(1)`
or `(1)/(sqrt(2))=(1)/(sqrt(m^(2)+1))`
or `m^(2)+1=2`
or `m= +-1`
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