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A straight line l1 with equation x-2y+10...

A straight line `l_1` with equation `x-2y+10=0` meets the circle with equation `x^2+y^2=100` at `B` in the first quadrant. A line through `B` perpendicular to `l_1` cuts the y-axis at `P(0,t)` . The value of `t` is (a)12 (b) 15 (c) 20 (d) 25

A

12

B

15

C

20

D

25

Text Solution

Verified by Experts

The correct Answer is:
3
Slope of `I_(1)=(1)/(2)`
Slope of `I_(2) = -2`
The equation of `I_(2)` is
`y= -2(x-10)`
or `y+2x=20`
Hence, `t=20`
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