A circle C whose radius is 1 unit touches the x-axis at point A. The center Q of C lies in the first quadrant. The tangent from the origin O to the circle touches it at T and a point P lies on its such that `Delta OAP` is a right - angles triangle at A and its perimeter is 8 units.
The length of PQ is

Options

A. `(x-2)^(2)+(y-1)^(2)=1`
B. `{x-(sqrt(3)-sqrt(2))}^(2)+(y-1)^(2)=1`
C. `(x-sqrt(3))^(2)+(y-1)^(2)=1`
D. none of these

Answer

1

Explanation

Now,` OA=2.`
So, center of the circle is `Q (2,1)`
Equation of circles is `( x-2)^(2)+ (y -1)^(2)=1`