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The circle passing through the point ( -...

The circle passing through the point `( -1,0)` and touching the y-axis at (0,2) also passes through the point.

A

`(-5,2)`

B

`(2,-5)`

C

`(5,-2)`

D

`(-2,5)`

Text Solution

Verified by Experts

The correct Answer is:
C
Let centre `C (3,k)`

As circle touches CX -axis.
`implies r=k`
So, circle is `(x-3)^(2)+(y-k)^(2) = k^(2)`
Given that it passes through `(1,-2)` ,br. `4+(k+2)^(2) = k^(2)`
`implies 4+k^(2)+4k+4=k^(2)`
`implies 4k = - 8`
`implies k = -2`
Circle is `(x-3)^(2) + (y+2)^(20=4`
Obviously` (5,-2)` satisfy the above equation.
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