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For how many values of p, the circle x^2...

For how many values of p, the circle `x^2+y^2+2x+4y-p=0` and the coordinate axes have exactly three common points?

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To determine how many values of \( p \) allow the circle given by the equation \( x^2 + y^2 + 2x + 4y - p = 0 \) to intersect the coordinate axes at exactly three points, we will analyze the conditions under which this occurs. ### Step 1: Rewrite the Circle Equation The equation of the circle can be rewritten in standard form by completing the square. 1. **Complete the square for \( x \) and \( y \)**: \[ x^2 + 2x + y^2 + 4y - p = 0 \] Completing the square for \( x \): \[ x^2 + 2x = (x+1)^2 - 1 \] Completing the square for \( y \): \[ y^2 + 4y = (y+2)^2 - 4 \] Substituting these back into the equation gives: \[ (x+1)^2 + (y+2)^2 - 5 - p = 0 \] Thus, the equation becomes: \[ (x+1)^2 + (y+2)^2 = p + 5 \] This represents a circle centered at \( (-1, -2) \) with radius \( \sqrt{p + 5} \). ### Step 2: Analyze Intersection with the Axes To find the conditions for the circle to intersect the coordinate axes at exactly three points, we consider different cases: #### Case 1: Circle passes through the origin - If \( p = 0 \), the equation becomes: \[ (x+1)^2 + (y+2)^2 = 5 \] The circle passes through the origin (0, 0), and it intersects the axes at three points: the origin and two more points on the axes. #### Case 2: Circle intersects the x-axis at two distinct points and touches the y-axis - The conditions for this case are: - The circle intersects the x-axis at two points: \( g^2 - c > 0 \) - The circle touches the y-axis: \( f^2 - c = 0 \) Here, \( g = 1 \), \( f = 4 \), and \( c = -p \): - From \( g^2 - c > 0 \): \[ 1^2 - (-p) > 0 \implies 1 + p > 0 \implies p > -1 \] - From \( f^2 - c = 0 \): \[ 4^2 - (-p) = 0 \implies 16 + p = 0 \implies p = -16 \] This case does not yield valid values since \( p = -16 \) does not satisfy \( p > -1 \). #### Case 3: Circle intersects the y-axis at two distinct points and touches the x-axis - The conditions for this case are: - The circle touches the x-axis: \( g^2 - c = 0 \) - The circle intersects the y-axis at two points: \( f^2 - c > 0 \) Using the same definitions: - From \( g^2 - c = 0 \): \[ 1^2 - (-p) = 0 \implies 1 + p = 0 \implies p = -1 \] - From \( f^2 - c > 0 \): \[ 4^2 - (-p) > 0 \implies 16 + p > 0 \implies p > -16 \] Here, \( p = -1 \) satisfies \( p > -16 \). ### Conclusion From the analysis, we find two possible values for \( p \): 1. \( p = 0 \) (circle passes through the origin) 2. \( p = -1 \) (circle touches the x-axis and intersects the y-axis at two points) Thus, the total number of values of \( p \) for which the circle and the coordinate axes have exactly three common points is **2**.

To determine how many values of \( p \) allow the circle given by the equation \( x^2 + y^2 + 2x + 4y - p = 0 \) to intersect the coordinate axes at exactly three points, we will analyze the conditions under which this occurs. ### Step 1: Rewrite the Circle Equation The equation of the circle can be rewritten in standard form by completing the square. 1. **Complete the square for \( x \) and \( y \)**: \[ x^2 + 2x + y^2 + 4y - p = 0 ...
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