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Base BC of triangle ABC is fixed and opp...

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that `tan.(B)/(2)tan.(C)/(2)` is constant. Prove that locus of vertex A is ellipse.

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To prove that the locus of vertex A is an ellipse under the given conditions, we will follow these steps: ### Step 1: Understand the Triangle and Given Condition Let triangle ABC have a fixed base BC. Let the lengths of the sides be denoted as follows: - BC = a (fixed) - AC = b - AB = c ...
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