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Let P be a pooint on the ellipse (x^(2)...

Let P be a pooint on the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1(agtb)` in the first or second quadrants whowse foci are `S_(1)and S_(2)`. Then the least possible value of circumradius of `DeltaPS_(1)S_(2)` will be

A

ae

B

be

C

`(ae)/(b)`

D

`(ae^(2))/(b)`

Text Solution

AI Generated Solution

To solve the problem, we need to find the least possible value of the circumradius \( R \) of triangle \( \Delta PS_1S_2 \), where \( P \) is a point on the ellipse given by the equation \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] with \( a > b \), and \( S_1 \) and \( S_2 \) are the foci of the ellipse. ...
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