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The foci of an ellipse are S(-1,-1), S'(...

The foci of an ellipse are `S(-1,-1), S'(0,-2) `its `e=1/2`, then the equation of the directrix corresponding to the focus S is

A

x-y+3-=0

B

x-y+7=0

C

x-y+5=0

D

x-y+4=0

Text Solution

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To find the equation of the directrix corresponding to the focus \( S(-1, -1) \) of the ellipse with eccentricity \( e = \frac{1}{2} \), we can follow these steps: ### Step 1: Identify the foci and eccentricity We are given the foci of the ellipse: - \( S(-1, -1) \) - \( S'(0, -2) \) The eccentricity \( e = \frac{1}{2} \). ...
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