A cruve is respresented by `C=21x^(2)-6xy+29y^(2)+6x-58y-151=0`
The eccentricity of the cruve is

Options

A. `1//3`
B. `1//sqrt(3)`
C. `2//3`
D. `2//sqrt(5)`

Explanation

To find the eccentricity of the curve represented by the equation \( C = 21x^2 - 6xy + 29y^2 + 6x - 58y - 151 = 0 \), we will follow these steps:

### Step 1: Identify the conic section
The given equation is a quadratic equation in \( x \) and \( y \). We can identify the type of conic section by calculating the discriminant \( D \):
\[ D = B^2 - 4AC \]
where \( A = 21 \), \( B = -6 \), and \( C = 29 \).
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