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A cruve is respresented by C=21x^(2)-6xy...

A cruve is respresented by `C=21x^(2)-6xy+29y^(2)+6x-58y-151=0`
The center of the conic C is

A

(1,0)

B

(0,0)

C

(0,1)

D

none of these

Text Solution

AI Generated Solution

To find the center of the conic represented by the equation \( C = 21x^2 - 6xy + 29y^2 + 6x - 58y - 151 = 0 \), we will follow these steps: ### Step 1: Rewrite the equation in standard form We start with the given equation: \[ 21x^2 - 6xy + 29y^2 + 6x - 58y - 151 = 0 \] ...
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