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The tagents at any point P of the circle...

The tagents at any point P of the circle `x^(2)+y^(2)=16` meets the tangents at a fixed point A at T. Point is joined to B, the other end of the diameter, through, A.
The sum of focal distance of any point on the curce is

A

12

B

16

C

20

D

8

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow the reasoning presented in the video transcript and derive the necessary equations. ### Step 1: Understand the Circle and Points We start with the circle given by the equation: \[ x^2 + y^2 = 16 \] This circle has a radius of \(4\) (since \(\sqrt{16} = 4\)) and is centered at the origin \((0, 0)\). The points \(A\) and \(B\) are defined as follows: ...
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