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An ellipse is drawn by taking a diameter...

An ellipse is drawn by taking a diameter of the circle `(x-1)^2+y^2=1` as its semi-minor axis and a diameter of the circle `x^2+(y-2)^2=4` as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) `4x^2+""y^2=""4` (2) `x^2+""4y^2=""8` (3) `4x^2+""y^2=""8` (4) `x^2+""4y^2=""16`

A

`4x^(2)+y^(2)=4`

B

`x^(2)+4y^(2)=8`

C

`4x^(2)+y^(2)=8`

D

`x^(2)+4y^(2)=16`

Text Solution

Verified by Experts

Length of semi-minor axis is 2
Length of semi-major axis is 4.
Then equation of elipse is `(x^(2))/(16)+(y^(2))/(4)=1 rArrx^(2)+4y^(2)=16`
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