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The radius of the circle passing through...

The radius of the circle passing through the foci of the ellipse `(x^2)/(16)+(y^2)/9` and having its center (0, 3) is 4 (b) 3 (c) `sqrt(12)` (d) `7/2`

A

`x^(2)+y^(2)-6y-7=0`

B

`x^(2)+y^(2)-6y+7=0`

C

`x^(2)+y^(2)-6y-5=0`

D

`x^(2)+y^(2)-6y+5=0`

Text Solution

Verified by Experts

Coordinates for focia re (ae, 0) , (-ar, 0)
`:. e=sqrt(1-(9)/(16))rArre=(sqrt(7))/(4)`
Coordinates of foci are `(sqrt(7),0),(-sqrt(7),0)`

Radius ` R=sqrt(7+9)=4`
Thus, equation of circle is `(x-0)^(2)+(y-3)^(2)=4^(2) or x^(2)+y^(2)-6y+9=16`
or `x^(2)+y^(2)-6y7=0`
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