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Let x=sin1^@ then find the value of the ...

Let `x=sin1^@` then find the value of the expression `1/(cos0^@cos1^@)+1/(cos1^@cos2^@)+....+1/(cos44^@cos45^@)`

A

x

B

`1//x`

C

`sqrt(2)//x`

D

`x//sqrt(2)`

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The correct Answer is:
To solve the expression \[ \frac{1}{\cos 0^\circ \cos 1^\circ} + \frac{1}{\cos 1^\circ \cos 2^\circ} + \ldots + \frac{1}{\cos 44^\circ \cos 45^\circ}, \] we start by letting \( x = \sin 1^\circ \). ### Step 1: Rewrite the expression We can rewrite each term in the expression by multiplying and dividing by \( \sin 1^\circ \): \[ \frac{1}{\cos k^\circ \cos (k+1)^\circ} = \frac{\sin 1^\circ}{\sin 1^\circ \cos k^\circ \cos (k+1)^\circ}. \] Thus, the entire expression becomes: \[ \sum_{k=0}^{44} \frac{\sin 1^\circ}{\cos k^\circ \cos (k+1)^\circ}. \] ### Step 2: Use the sine subtraction formula Using the identity \( \sin A - \sin B = 2 \cos\left(\frac{A+B}{2}\right) \sin\left(\frac{A-B}{2}\right) \), we can express: \[ \sin(k+1)^\circ - \sin k^\circ = 2 \cos\left(\frac{(k+1)+k}{2}\right) \sin\left(\frac{(k+1)-k}{2}\right) = 2 \cos\left(k + \frac{1}{2}\right) \sin\left(\frac{1}{2}\right). \] ### Step 3: Substitute back into the expression Now, we can rewrite the sum as: \[ \sum_{k=0}^{44} \frac{\sin 1^\circ}{\cos k^\circ \cos (k+1)^\circ} = \sum_{k=0}^{44} \frac{\sin 1^\circ}{\frac{1}{2}(\sin(k+1)^\circ - \sin k^\circ)}. \] ### Step 4: Simplify the expression This simplifies to: \[ \sum_{k=0}^{44} \frac{2 \sin 1^\circ}{\sin(k+1)^\circ - \sin k^\circ}. \] ### Step 5: Telescoping series Notice that this forms a telescoping series. Most terms will cancel out: \[ 2 \sin 1^\circ \left( \tan 1^\circ + \tan 2^\circ - \tan 1^\circ + \tan 3^\circ - \tan 2^\circ + \ldots + \tan 45^\circ - \tan 44^\circ \right). \] ### Step 6: Final simplification The only terms that do not cancel are \( \tan 45^\circ \) and \( \tan 0^\circ \): \[ = 2 \sin 1^\circ \cdot \tan 45^\circ = 2 \sin 1^\circ \cdot 1 = 2 \sin 1^\circ. \] ### Step 7: Substitute back for \( x \) Since \( x = \sin 1^\circ \), we have: \[ \frac{1}{\cos 0^\circ \cos 1^\circ} + \frac{1}{\cos 1^\circ \cos 2^\circ} + \ldots + \frac{1}{\cos 44^\circ \cos 45^\circ} = \frac{2}{x}. \] ### Final Answer Thus, the value of the expression is: \[ \frac{2}{\sin 1^\circ}. \]

To solve the expression \[ \frac{1}{\cos 0^\circ \cos 1^\circ} + \frac{1}{\cos 1^\circ \cos 2^\circ} + \ldots + \frac{1}{\cos 44^\circ \cos 45^\circ}, \] we start by letting \( x = \sin 1^\circ \). ...
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