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If the equation sin^2 x-a sin x + b = 0 ...

If the equation `sin^2 x-a sin x + b = 0` has only one solution in `(0, pi)` then which of the following statements are correct?

A

`a in (-oo, 1] uu [2, oo)`

B

`b in (-oo, 0] uu [1, oo)`

C

`a=1+b`

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the quadratic equation given by: \[ \sin^2 x - a \sin x + b = 0 \] We want to find the conditions under which this equation has only one solution in the interval \( (0, \pi) \). ### Step 1: Identify the nature of the roots For a quadratic equation \( Ax^2 + Bx + C = 0 \) to have only one solution, the discriminant must be zero. The discriminant \( D \) is given by: \[ D = B^2 - 4AC \] In our case, we have: - \( A = 1 \) - \( B = -a \) - \( C = b \) Thus, the discriminant becomes: \[ D = (-a)^2 - 4(1)(b) = a^2 - 4b \] For the equation to have only one solution, we need: \[ a^2 - 4b = 0 \] ### Step 2: Solve for \( b \) From the equation \( a^2 - 4b = 0 \), we can express \( b \) in terms of \( a \): \[ b = \frac{a^2}{4} \] ### Step 3: Analyze the range of \( \sin x \) The function \( \sin x \) takes values in the interval \( [0, 1] \) for \( x \in (0, \pi) \). Therefore, for the quadratic equation to have real solutions, we need: \[ 0 \leq \sin x \leq 1 \] This implies that the roots of the equation \( \sin^2 x - a \sin x + b = 0 \) must lie within the interval \( [0, 1] \). ### Step 4: Determine conditions on \( a \) and \( b \) Since we have \( b = \frac{a^2}{4} \), we need to ensure that both roots of the quadratic equation fall within the interval \( [0, 1] \). 1. The vertex of the parabola represented by the quadratic equation occurs at: \[ \sin x = \frac{a}{2} \] For the equation to have only one solution, the vertex must lie within the interval \( [0, 1] \): \[ 0 \leq \frac{a}{2} \leq 1 \implies 0 \leq a \leq 2 \] 2. Additionally, since \( b = \frac{a^2}{4} \), we have: \[ b \geq 0 \implies \frac{a^2}{4} \geq 0 \implies a \text{ can be any real number.} \] ### Conclusion From the analysis, we conclude that: - \( a \) must be in the range \( [0, 2] \). - \( b \) must be non-negative and can be expressed as \( b = \frac{a^2}{4} \).

To solve the problem, we need to analyze the quadratic equation given by: \[ \sin^2 x - a \sin x + b = 0 \] We want to find the conditions under which this equation has only one solution in the interval \( (0, \pi) \). ...
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