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If in a Delta ABC, tanA+tanB+tanC=6 then...

If in a `Delta ABC, tanA+tanB+tanC=6` then `cotA cotB cot C=` `a.6, b. 1, c. 1/6, d.` none of these

A

`1/6`

B

1

C

6

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`tan A+tan B+tn C`
= tna A tan B tna C = 6
`therefore cot A cot B cot C = 1//6`
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