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If tanbeta = costheta*tanalpha , then ...

If `tanbeta = costheta*tanalpha` , then `tan^2(theta/2)` is equal to

A

`(sin(alpha+beta))/(sin(alpha-beta))`

B

`(cos(alpha-beta))/(cos(alpha+beta))`

C

`(sin(alpha-beta))/(sin(alpha+beta))`

D

`(cos(alpha+beta))/(cos(alpha-beta))`

Text Solution

Verified by Experts

The correct Answer is:
C
`"tan"^(2)(theta)/(2)=(1-cos theta)/(1+cos theta)=(tan alpha - tan beta)/(tan alpha + tan beta)=(sin(alpha-beta))/(sin(alpha+beta))`
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