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Find the angle of vector veca=6hati+2hat...

Find the angle of vector `veca=6hati+2hatj-3hatk` with `x`-axis.

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To find the angle of the vector \(\vec{A} = 6\hat{i} + 2\hat{j} - 3\hat{k}\) with the x-axis, we can follow these steps: ### Step 1: Identify the components of the vector The vector \(\vec{A}\) has the following components: - \(A_x = 6\) (the coefficient of \(\hat{i}\)) - \(A_y = 2\) (the coefficient of \(\hat{j}\)) - \(A_z = -3\) (the coefficient of \(\hat{k}\)) ...
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The angle made by the vector vecA=2hati+3hatj with Y-axis is

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Knowledge Check

  • The angle subtended by vector vecA = 4 hati + 3hatj + 12hatk with the x-axis is :

    A
    `sin^(-1) (3/13)`
    B
    `sin^(-1) (4/13)`
    C
    `cos^(-1)(4/13)`
    D
    `cos^(-1)(3/13)`
  • The number of unit vectors perpendicular to the plane of vectors veca=2hati-6hat j-3hatk and vecb=4hati+3hatj-hatk is/are

    A
    1
    B
    2
    C
    0
    D
    None of these
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