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veca=2veci+vecj+veck, vecb=b(1)hati+b(2)...

`veca=2veci+vecj+veck`, `vecb=b_(1)hati+b_(2)hatj+b_(3)hatk`,
`veca xx vecb=5hati+2hatj-12hatk, veca.vecb=11`, then `b_(1)+b_(2)+b_(3)=`

A

3

B

5

C

7

D

9

Text Solution

Verified by Experts

The correct Answer is:
B
`vecb= ((vecaxxvecb)xx veca+(veca.vecb)veca)/(|veca|^(2))`
`=6hati-3hatj+2hatk`
`rArr vecb_(1)+vecb_(2)+vecb_(3)=6-3+2=5`
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