If `(a^2-1)x^2+(a-1)x+a^2-4a+3=0` is identity in `x` , then find the value of `a` .

Explanation

The given relation is satisfied for all real values of x, so all the coefficients must be zero. Then,
`{:(a^(2)-1 = 0 rArr a = pm1),(a- 1 = 0 rArr a = 1),(a^(2)- 4a +3=0rArr a = 1","3 ):}}` common value of a is 1