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If x + y + z = 12, x^(2) + Y^(2) + z^(2)...

If `x + y + z = 12, x^(2) + Y^(2) + z^(2) = 96` and `(1)/(x)+(1)/(y)+(1)/(z)= 36` . Then find the value `x^(3) + y^(3)+z^(3).`

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To find the value of \( x^3 + y^3 + z^3 \) given the equations: 1. \( x + y + z = 12 \) 2. \( x^2 + y^2 + z^2 = 96 \) 3. \( \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 36 \) We can use the identity: ...
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