If `alpha,beta` are the roots of the equation `2x^2-35x+2=0` , the find the value of `(2alpha-35)^3(2beta-35)^3dot`

Explanation

To solve the problem, we need to find the value of \((2\alpha - 35)^3(2\beta - 35)^3\) where \(\alpha\) and \(\beta\) are the roots of the equation \(2x^2 - 35x + 2 = 0\).

### Step 1: Identify the roots of the equation
The roots \(\alpha\) and \(\beta\) can be found using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here, \(a = 2\), \(b = -35\), and \(c = 2\).
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