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The total number of integral values of a...

The total number of integral values of a so that `x^2-(a+1)x+a-1=0` has integral roots is equal to a. `1` b. `2` c. `4` d. none of these

A

1

B

2

C

4

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
1
`x^(2) - (a + 1)x + a - 1 = 0`
`rArr (x - a) (x - 1) = 1`
Now, `a in I` and we want x to be an integer. Hence,
`x - a = 1, x - 1 = 1` or `x - a = -1, x - 1 = -1`
`rArr a = 1` in both cases
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