The root of the equation `2(1 + i) x^2-4(2-i) x-5-3 i = 0,` where `i = sqrt(-1),` which has greater modulus is

Explanation

To find the root of the equation \(2(1 + i)x^2 - 4(2 - i)x - (5 + 3i) = 0\) that has the greater modulus, we will use the quadratic formula. The quadratic formula states that for an equation of the form \(ax^2 + bx + c = 0\), the roots can be found using:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

### Step 1: Identify coefficients
From the given equation, we can identify:
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