If `(sqrt(8)+i)^(50)=3^(49)(a+i b)` , then find the value of `a^2+b^2dot`

Explanation

Given that
`(sqrt(8) +i)^(50) = 3^(49) (a+ib)`
Taking modulus and squaring both sides, we get
`(8+1)^(50) = ^(98) (a^(2) + b^(2))`
`or 9^(50) = 3^(98) (a^(2) + b^(2))`
` 3^(100) = 3^(98) (a^(2) + b^(2))`
` or (a^(2) + b^(2)) =9`