Find the point of intersection of the curves `a r g(z-3i)=(3pi)/4a n d arg(2z+1-2i)=pi//4.`

Explanation

To find the point of intersection of the curves defined by the arguments given in the problem, we will follow these steps:

### Step 1: Understand the first equation
The first equation is:
\[ \arg(z - 3i) = \frac{3\pi}{4} \]
This means that the point \( z \) lies on a ray that starts from the point \( 3i \) (which is \( (0, 3) \) in Cartesian coordinates) and makes an angle of \( \frac{3\pi}{4} \) with the positive x-axis.
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