In the Argands plane what is the locus of `z(!=1)` such that `a rg{3/2((2z^2-5z+3)/(2z^2-z-2))}=(2pi)/3dot`

Explanation

To solve the problem, we need to find the locus of the complex number \( z \) in the Argand plane such that

\[ \arg\left(\frac{3}{2} \cdot \frac{2z^2 - 5z + 3}{2z^2 - z - 2}\right) = \frac{2\pi}{3}. \]

### Step 1: Rewrite the equation
We start with the equation:
...