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If one root of the equation z^2-a z+a-1=...

If one root of the equation `z^2-a z+a-1= 0` is (1+i), where a is a complex number then find the root.

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The correct Answer is:
z=1
`z^(2) -az + a 1 =0`
Putting z = 1 + i
a=2+i
`rArr z^(2) - (2+i)z + 1 + i=0` is the equaiton
`rArr z = 1` is the other roots
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