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Complex number z lies on the curve S-=...

Complex number z lies on the curve `S-= arg(z+3)/(z+3i) =-(pi)/(4)`

A

`{:(,,"a","b","c","d"),(,"(1)","p","q","p","r"):}`

B

`{:(,,"a","b","c","d"),(,"(2)","s","r","q","p"):}`

C

`{:(,,"a","b","c","d"),(,"(3)","q","p","q","r"):}`

D

`{:(,,"a","b","c","d"),(,"(4)","s","p","q","r"):}`

Text Solution

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The correct Answer is:
To solve the problem where the complex number \( z \) lies on the curve defined by the equation \[ S = \frac{\arg(z + 3)}{z + 3i} = -\frac{\pi}{4}, \] we will follow these steps: ### Step 1: Rewrite the equation We start by rewriting the equation in a more manageable form. We know that \[ \arg(z + 3) = -\frac{\pi}{4} \cdot (z + 3i). \] ### Step 2: Express \( z \) in terms of \( x \) and \( y \) Let \( z = x + yi \), where \( x \) and \( y \) are real numbers. Then we can express \( z + 3 \) as: \[ z + 3 = (x + 3) + yi. \] ### Step 3: Find the argument The argument of a complex number \( a + bi \) is given by \[ \arg(a + bi) = \tan^{-1}\left(\frac{b}{a}\right). \] Thus, we have: \[ \arg(z + 3) = \tan^{-1}\left(\frac{y}{x + 3}\right). \] ### Step 4: Substitute into the equation Substituting this into our equation gives us: \[ \frac{\tan^{-1}\left(\frac{y}{x + 3}\right)}{(x + 3) + yi} = -\frac{\pi}{4}. \] ### Step 5: Multiply both sides by \( (x + 3) + yi \) To eliminate the denominator, we multiply both sides by \( (x + 3) + yi \): \[ \tan^{-1}\left(\frac{y}{x + 3}\right) = -\frac{\pi}{4} \cdot ((x + 3) + yi). \] ### Step 6: Analyze the equation From the equation above, we can analyze the real and imaginary parts. The left-hand side is a real number, while the right-hand side is a complex number. For the equality to hold, the imaginary part must be zero. Thus: \[ -\frac{\pi}{4} \cdot y = 0 \implies y = 0. \] ### Step 7: Substitute \( y = 0 \) Now substituting \( y = 0 \) back into our expression for \( z \): \[ z = x + 0i = x. \] ### Step 8: Solve for \( x \) Now we need to find the values of \( x \) that satisfy the original equation. Since \( y = 0 \), we have: \[ \arg(z + 3) = \arg(x + 3) = \tan^{-1}\left(\frac{0}{x + 3}\right) = 0. \] Thus, we need to find \( x \) such that: \[ 0 = -\frac{\pi}{4} \cdot (x + 3). \] This implies: \[ x + 3 = 0 \implies x = -3. \] ### Final Result Thus, the complex number \( z \) that lies on the curve is: \[ z = -3. \]
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