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If `a , b ,and c` are respectively, the pth, qth , and rth terms of a G.P., show that `(q-r)loga+(r-p)logb+(p-q)logc=0.`

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To solve the problem, we need to show that if \( a, b, c \) are respectively the \( p \)-th, \( q \)-th, and \( r \)-th terms of a geometric progression (G.P.), then the equation \[ (q - r) \log a + (r - p) \log b + (p - q) \log c = 0 \] holds true. ...
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