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In a conference 10 speakers are present....

In a conference 10 speakers are present. If `S_1` wants to speak before `S_2a n dS_2` wants to speak after `S_3,` then find the number of ways all the 10 speakers can give their speeches with the above restriction if the remaining seven speakers have no objection to speak at any number.

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To solve the problem step by step, we need to consider the conditions given for the speakers and how they can be arranged. ### Step 1: Identify the conditions We have 10 speakers: S1, S2, S3, and 7 others. The conditions are: - S1 must speak before S2. - S2 must speak after S3. ### Step 2: Determine the valid arrangements of S1, S2, and S3 ...
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