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Minimum integral value of k for which th...

Minimum integral value of k for which the equation `e^(x)=kx^(2)` has exactly three real distinct solution,

A

1

B

2

C

3

D

4

Text Solution

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The correct Answer is:
To find the minimum integral value of \( k \) for which the equation \( e^x = kx^2 \) has exactly three real distinct solutions, we can follow these steps: ### Step 1: Rewrite the equation We start with the equation: \[ e^x = kx^2 \] We can rearrange this to: \[ f(x) = \frac{e^x}{x^2} = k \] ### Step 2: Analyze the function \( f(x) \) Define the function: \[ f(x) = \frac{e^x}{x^2} \] We need to analyze the behavior of \( f(x) \) to find the values of \( k \) that yield three distinct solutions. ### Step 3: Find the derivative \( f'(x) \) To find the critical points of \( f(x) \), we compute the derivative: \[ f'(x) = \frac{(e^x \cdot x^2)' - (e^x \cdot (x^2)')}{(x^2)^2} \] Using the quotient rule, we get: \[ f'(x) = \frac{e^x x^2 - e^x \cdot 2x}{x^4} = \frac{e^x (x^2 - 2x)}{x^4} \] Setting \( f'(x) = 0 \) gives us: \[ e^x (x^2 - 2x) = 0 \] Since \( e^x \) is never zero, we solve: \[ x^2 - 2x = 0 \Rightarrow x(x - 2) = 0 \] Thus, \( x = 0 \) or \( x = 2 \). ### Step 4: Determine the nature of critical points We check the second derivative or the sign of \( f'(x) \) around the critical points: - For \( x < 0 \), \( f'(x) < 0 \) (decreasing). - At \( x = 0 \), \( f(x) \) approaches infinity. - For \( 0 < x < 2 \), \( f'(x) > 0 \) (increasing). - At \( x = 2 \), we check \( f(2) = \frac{e^2}{4} \). - For \( x > 2 \), \( f'(x) < 0 \) (decreasing). ### Step 5: Find the minimum value of \( k \) The function \( f(x) \) has a minimum at \( x = 2 \): \[ f(2) = \frac{e^2}{4} \] For the equation \( e^x = kx^2 \) to have exactly three distinct solutions, \( k \) must be greater than this minimum value: \[ k > \frac{e^2}{4} \] Calculating \( \frac{e^2}{4} \): Using \( e \approx 2.718 \): \[ e^2 \approx 7.389 \Rightarrow \frac{e^2}{4} \approx 1.847 \] Thus, the smallest integer \( k \) satisfying this inequality is: \[ k \geq 2 \] ### Conclusion The minimum integral value of \( k \) for which the equation \( e^x = kx^2 \) has exactly three real distinct solutions is: \[ \boxed{2} \]

To find the minimum integral value of \( k \) for which the equation \( e^x = kx^2 \) has exactly three real distinct solutions, we can follow these steps: ### Step 1: Rewrite the equation We start with the equation: \[ e^x = kx^2 \] We can rearrange this to: ...
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