Home
Class 12
MATHS
Show that the segment of the tangent to ...

Show that the segment of the tangent to the curve `y=a/2I n((a+sqrt(a^2-x^2))/(a-sqrt(a^2-x^2)))-sqrt(a^2-x^2)` contained between the y=axis and the point of tangency has a constant length.

Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise MATRIX MATCH TYPE|3 Videos

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise ILLUSTRATION|62 Videos

  • 3D COORDINATION SYSTEM

    CENGAGE ENGLISH|Exercise DPP 3.1|11 Videos

  • APPLICATION OF INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|142 Videos

Similar Questions

Explore conceptually related problems

y=tan^(-1)((sqrt(1+x^2)+sqrt(1-x^2))/(sqrt(1+x^2)-sqrt(1-x^2)))

Prove that the portion of the tangent to the curve (x+sqrt(a^2-y^2))/a=(log)_e(a+sqrt(a^2-y^2))/y intercepted between the point of contact and the x-axis is constant.

The tangent at a point P on the curve y =ln ((2+ sqrt(4-x ^(2)))/(2- sqrt(4-x ^(2))))-sqrt(4-x ^(2)) meets the y-axis at T, then PT^(2) equals to :

Find the equation of tangent to the curve y=sin^(-1)(2x)/(1+x^2)a tx=sqrt(3)

Find the equation of the tangent to the curve sqrt(x)+sqrt(y)=a , at the point ((a^2)/4,(a^2)/4)dot

Identify the curve sqrt((x+1)^(2)+y^(2))+ sqrt(x^(2)+(y-1)^(2))-2 =0

The length of the tangent of the curve y=x^(2)+1 at (1 ,3) is (A) sqrt(5) (B) 3sqrt(5) (C) 1/2 (D) 3(sqrt(5))/(2)

The area between the curves y=sqrt(x),y=x^(2) is

Aea of the region nclosed between the curves x=y^2-1 and x=|y|sqrt(1-y^2) is

Find the point at which the tangent to the curve y=sqrt(4x-3)-1 has its slope 2/3 .