Home
Class 12
MATHS
Which of the following statements is alw...

Which of the following statements is always true? ([.] represents the greatest integer function. a) If f(x) is discontinuous then `|f(x)|` is discontinuous b) If `f(x)` is discontinuous then f(|x|) is discontinuous c) f(x)=[g(x)] is discontinous when `g(x) is an integer d) none of these

A

if f(x) is discontinuous then |f(x)| is discontinuous

B

if f(x) is discontinuous , then f(|x|) is discontinuous .

C

f(x) =[g(x) ] is discontinuous , when g(x) is an integer

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given statements, we will evaluate each option one by one to determine which statement is always true. ### Given Statements: 1. **Option a:** If \( f(x) \) is discontinuous, then \( |f(x)| \) is discontinuous. 2. **Option b:** If \( f(x) \) is discontinuous, then \( f(|x|) \) is discontinuous. 3. **Option c:** \( f(x) = \lfloor g(x) \rfloor \) is discontinuous when \( g(x) \) is an integer. 4. **Option d:** None of these. ### Step-by-Step Solution: #### Step 1: Analyze Option a - **Statement:** If \( f(x) \) is discontinuous, then \( |f(x)| \) is discontinuous. - **Counterexample:** Consider \( f(x) = x \) for \( x \neq 0 \) and \( f(0) = 1 \). Here, \( f(x) \) is discontinuous at \( x = 0 \). However, \( |f(x)| = |x| \) is continuous everywhere. - **Conclusion:** This statement is **not always true**. #### Step 2: Analyze Option b - **Statement:** If \( f(x) \) is discontinuous, then \( f(|x|) \) is discontinuous. - **Counterexample:** Let \( f(x) = \begin{cases} 1 & \text{if } x < 0 \\ 0 & \text{if } x = 0 \\ 1 & \text{if } x > 0 \end{cases} \). Here, \( f(x) \) is discontinuous at \( x = 0 \), but \( f(|x|) \) is continuous for all \( x \). - **Conclusion:** This statement is **not always true**. #### Step 3: Analyze Option c - **Statement:** \( f(x) = \lfloor g(x) \rfloor \) is discontinuous when \( g(x) \) is an integer. - **Explanation:** The greatest integer function \( \lfloor g(x) \rfloor \) is discontinuous at points where \( g(x) \) is an integer because it jumps at those points. If \( g(x) \) takes integer values, then \( \lfloor g(x) \rfloor \) will indeed be discontinuous at those points. - **Conclusion:** This statement is **always true**. #### Step 4: Analyze Option d - Since we have found that option c is always true, option d (none of these) is incorrect. ### Final Answer: The correct answer is **Option c**: \( f(x) = \lfloor g(x) \rfloor \) is discontinuous when \( g(x) \) is an integer. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The function f(x)=tanx is discontinuous on the set

The function f(x) =cot x is discontinuous on set

The function f(x) =cot x is discontinuous on set

The functions g(x)=x-[x] is discontinuous at x =

f+g may be a continuous function, if (a) f is continuous and g is discontinuous

Find the value of x in [1,3] where the function [x^2+1]([dot] represents the greatest integer function) is discontinuous.

Statement I f(x) = sin x + [x] is discontinuous at x = 0. Statement II If g(x) is continuous and f(x) is discontinuous, then g(x) + f(x) will necessarily be discontinuous at x = a.

Statement 1: f(x)=cos x is continous at x=0a n dg(x)=[tanx],"w h e r e"[dot] represents greatest integer function, is discontinuous at x=0,t h e nh(x)=f(x)dotg(x) is discontinuous at x=0. Statement 2: If f(x) is continous and g(x) is discontinuous at x=a ,t h e nh(x)=f(x)g(x) is discontinuous at x=a

The function f(x) = [x] cos((2x-1)/2) pi where [ ] denotes the greatest integer function, is discontinuous

If f(x) = sec 2x + cosec 2x, then f(x) is discontinuous at all points in