Show that the function f(x)={x^msin(1/x)...

Show that the function `f(x)={x^msin(1/x),\ \ \ x!=0 ` , `0\ \ x=0` is continuous but not differentiable at `x=0` , if (0 < m<1)

A

`a in (-1,0)`

B

`a in (0,2]`

C

`a in (0,1]`

D

`a in [1,2}`

Verified by Experts

The correct Answer is:

C

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