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Show that the line segments joining the mid-points of opposite sides of a quadrilateral bisects each other.

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To show that the line segments joining the midpoints of opposite sides of a quadrilateral bisect each other, we can follow these steps: ### Step 1: Define the Quadrilateral Let the vertices of the quadrilateral be represented by position vectors: - Vertex A: \(\vec{A}\) - Vertex B: \(\vec{B}\) - Vertex C: \(\vec{C}\) - Vertex D: \(\vec{D}\) ...
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RD SHARMA ENGLISH-ALGEBRA OF VECTORS-All Questions
  1. Show that the point 2 hat i ,- hat i-4 hat j and - hat i+4 hat j fr...

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  2. If vec a be the position vector whose tip is (5,-3), find the c...

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  3. Show that the line segments joining the mid-points of opposite side...

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  4. A B C D are four points in a plane and Q is the point of interse...

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  5. If vec aa n d vec b are non-collinear vectors, find the value of x fo...

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  6. The projection of a vector on the coordinate axes are (6,-3,2) Find ...

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  7. If vec a , vec b, vec c are three non- null vectors such that any tw...

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  8. Show that the vectors 2 vec a- vec b+3 vec c , vec a+ vec b-2 vec ca n...

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  9. Show that the points A ,B ,C with position vectors -2 vec a+3 vec b+5 ...

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  10. Prove that the line joining the mid-points of the diagonals of a trape...

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  11. Prove that the segment joining the middle points of two non-paralle...

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  12. Using vector method, prove that the line segments joining the mid-p...

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  13. If the points with position vectors 60 hat i+2 hat j , 40 hat i-8 hat ...

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  14. If A B C D is quadrilateral and Ea n dF are the mid-points of A Ca n d...

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  15. If D and E are the mid-points of sides AB and AC of a triangle A B C r...

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  16. If G is the centroid of a triangle A B C , prove that vec G A+ vec G ...

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  17. Prove using vectors: Medians of a triangle are concurrent.

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  18. Points L, M, N divide the sides BC, CA, AB of ABC in the ratio 1:4, 3:...

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  19. Prove using vectors: The diagonals of a quadrilateral bisect each o...

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  20. Show that the line segments joining the mid-points of opposite side...

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