Evaluate: `intsqrt((1-sin2x)/(1+sin2x))dx`

Explanation

To evaluate the integral \( \int \sqrt{\frac{1 - \sin 2x}{1 + \sin 2x}} \, dx \), we will follow a systematic approach:

### Step 1: Rewrite the Integral
We start with the integral:
\[ I = \int \sqrt{\frac{1 - \sin 2x}{1 + \sin 2x}} \, dx \]
We know that \( \sin 2x = 2 \sin x \cos x \). Thus, we can express \( 1 - \sin 2x \) and \( 1 + \sin 2x \) in terms of \( \sin x \) and \( \cos x \).
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