Find the approximate value of `(log)_(10)1005` , given that `(log)_(10)e=0. 4343`

Explanation

To find the approximate value of \( \log_{10} 1005 \) given that \( \log_{10} e = 0.4343 \), we can use differentials. Here’s a step-by-step solution:

### Step 1: Identify the known values
We know:
- \( \log_{10} e = 0.4343 \)
- We want to find \( \log_{10} 1005 \)

### Step 2: Set up the function
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