Find the point on the curve `y=x^2` where the slope of the tangent is equal to the `x-` coordinate of the point.

Explanation

To find the point on the curve \( y = x^2 \) where the slope of the tangent is equal to the \( x \)-coordinate of the point, we can follow these steps:

### Step 1: Define the point on the curve
Let the point on the curve be \( (x_1, y_1) \). Since the curve is defined by \( y = x^2 \), we have:
\[ y_1 = x_1^2 \]

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