Find the equation of the normal to the curve `x^2+2y^2-4x-6y+8=0` at the point whose abscissa is 2.

Explanation

To find the equation of the normal to the curve \( x^2 + 2y^2 - 4x - 6y + 8 = 0 \) at the point where the abscissa is 2, we will follow these steps:

### Step 1: Find the corresponding y-coordinates for x = 2
Substituting \( x = 2 \) into the curve equation:

\[ 2^2 + 2y^2 - 4(2) - 6y + 8 = 0 \]
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