For what value of `k` is the function `f(x)={(x^2-1)/(x-1),` `,x!=1,k,x=1" continuous at"x=1?`

Explanation

To determine the value of \( k \) for which the function

\[
f(x) =
\begin{cases}
\frac{x^2 - 1}{x - 1} & \text{if } x \neq 1 \\
k & \text{if } x = 1
\end{cases}
...