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Let A={x in R :0lt=xlt=1}dot If f: A->A...

Let `A={x in R :0lt=xlt=1}dot` If `f: A->A` is defined by `f(x)={(x ,, if x in Q) , (1-x ,, if x!in Q):}` then prove that `fof(x)=x` for all `x in Adot`

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