Prove that : `tan^(-1)(2/11)+tan^(-1)(7/24)=tan^(-1)(1/2)`

Explanation

To prove that \( \tan^{-1}\left(\frac{2}{11}\right) + \tan^{-1}\left(\frac{7}{24}\right) = \tan^{-1}\left(\frac{1}{2}\right) \), we will use the formula for the sum of inverse tangents:

\[ \tan^{-1}(x) + \tan^{-1}(y) = \tan^{-1}\left(\frac{x + y}{1 - xy}\right) \]

provided that \( xy < 1 \).

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