Evaluate: `tan(2tan^(-1)(1/5))`

Explanation

To evaluate \( \tan(2\tan^{-1}(\frac{1}{5})) \), we can use the double angle formula for tangent, which states:

\[ \tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)} \]

Here, we can let \( \theta = \tan^{-1}(\frac{1}{5}) \). Thus, we have:

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