Find `x` if `` `tan^(-1)(sqrt(3))+cot^(-1)x=pi/2`

If tan^(-1)(sqrt(3))+cot^(-1)x=pi/2 , find xdot

Solve: 5tan^(-1)x+3cot^(-1)x=2pi

Find the value of tan^(-1)(-1/(sqrt(3)))+cot^(-1)((1)/(sqrt(3))) + tan^(-1)[sin((-pi)/(2))] .

Solve: tan^(-1)x+2cot^(-1)x=(2pi)/3

Solve for x : tan^(-1)x+2cot^(-1)x=(2pi)/3

Find the value of tan^(-1) sqrt3 - cot^(-1) (-sqrt3)

If -1< x < 0 , then cos^(-1)x is equal to (a) sec^(-1)(1/ x) (b) pi-sin^(-1)sqrt(1+x^2) (c) pi+tan^(-1)(x/(sqrt(1-x^2))) (d) cot^(-1)(x/(sqrt(1-x^2))) .

Evaluate each of the following: (i) "cosec"^(-1)(-2/(sqrt(3)))+2cot^(-1)(-1) (ii) tan^(-1)(-1/(sqrt(3)))+cot^(-1)(1/(sqrt(3)))+tan^(-1)(sin(-pi/2))

Find the principal values of each of the following: (i) cot^(-1)(-1/(sqrt(3))) (ii) cot^(-1)(tan((3pi)/4))

It is given that A=(tan^(-1)x)^(3)+(cot^(-1)x)^(3) where x gt 0 and B=(cos^(-1)t)^(2)+(sin^(-1)t)^(2) where t in [0, (1)/(sqrt(2))] , and sin^(-1)x+cos^(-1)x=(pi)/(2) for -1 le x le 1 and tan^(-1)x +cot^(-1)x=(pi)/(2) for x in R . The interval in which A lies is :