If `f(x)={(1-cos10x)/(x^2a),x<0(sqrt(x))/(sqrt(625)+sqrt(x)-25),x >0,x=0` then the value of a so that `f(x)` may be continuous at `x=0,i s` 25 (b) `-1` (c) 1 (d) indeterminate

Explanation

To determine the value of \( a \) such that the function

\[
f(x) =
\begin{cases}
\frac{1 - \cos(10x)}{x^2 a}, & x < 0 \\
\frac{\sqrt{x}}{\sqrt{625} + \sqrt{x} - 25}, & x > 0 \\
0, & x = 0
...