If `f(x)={(2^(x+2)-16)/(4^x-16)`, if `x!=2`, k if `x=2` is continuous at `x=2` , find k

Explanation

To find the value of \( k \) such that the function

\[
f(x) =
\begin{cases}
\frac{2^{x+2} - 16}{4^x - 16} & \text{if } x \neq 2 \\
k & \text{if } x = 2
\end{cases}
...