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If the function `f(x)` defined by f(x)=`(log(1+3x)-"log"(1-2x))/x `, `x!=0` and k , x=0. Find k.

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`f(x) = (log(1+3x) - log(1-2x))/x`
`l = lim_(x->0) (log(1+3x) - log(1-2x))/x`
`l = lim_(x->0) (1/(1+3x) * 3 - 1/(1-2x) (-2))/1`
`l = lim_(x->0) 3/(1+3x) + 2/(1-2x) `
`l = 3/1 + 2/1 = 5`
`f(0) = f(0^-) = f(0^+)`
`k = 5`
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